Past exam of the mathematics course of the University of Cambridge / 2025 / iii / Paper 307 / 1 / ii / Solution

A vector superfield is a real superfield,For a non-Abelian gauge theory it is also Lie-algebra valued, $V=V^a{T}_a$. The reality condition permits the component expansion to be reduced to Wess-Zumino gauge, where the physical fields are a gauge field and gaugino together with a real auxiliary field.