 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ia/paper-2/6c/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

d U / d t = \nabla U \cdot (- \nabla U) = - ∣\nabla U ∣^{2} \leq 0

. The descending gradient flow trajectory from

(2, 1)

stays in its bounded contour basin and tends to the only critical point there,

(1, 0)

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