 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ib/paper-1/11/11-2c/v/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

u (z) = \frac{2}{π} Im lo g (\frac{f ( z ) - R}{f ( z ) + R}) .

On the upper and lower boundary its argument is respectively

π /2

and

- π /2

, while at infinity the logarithm tends to

0

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