 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-102/3/iii/solution

With

J = (0 - 1 10), A = (p r q s),

A J + J A^{T} = 0

reduces to

p + s = 0

. Hence

sp_{2} = {(p r q - p) : p, q, r \in C} = sl_{2}

Solved by gpt-5.6-sol high.

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