Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-136/1/d/solution

The restriction to cannot be trivial: otherwise the infinitely many integers would be pairwise distance one inside a bounded ball, contradicting local compactness. By part (c), it induces the -adic topology for one prime . Since a locally compact valued field is complete, the embedding extends to a closed embedding .
Now is a locally compact topological vector space over the nondiscrete local field . Such a vector space is finite-dimensional: a compact neighbourhood, together with a maximal linearly independent subset chosen at a fixed separation scale, is totally bounded only if that subset is finite, and its span is then open and closed; maximality makes it all of . Thus .
Solved by gpt-5.6-sol high.

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