Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-346/4/solution

For either component and , direct integration of the power law density gives
Let . Since ,
The additive constants depend on the chosen reference and cannot generally be set by requiring at infinity for an untruncated power law.
For a satellite on a circular orbit, the linearized effective radial force gives the tidal radius
Here and , so
Substitution of the two mass profiles yields
and equivalently
Now set . Then
The host circular speed is with . The magnitude of Chandrasekhar dynamical friction becomes
a constant. The specific angular momentum is . Since the drag torque gives ,
and therefore
Integration gives
which is finite.
If stripping is switched off, hold the satellite mass at its initial value . The frictional acceleration is then , where is the constant acceleration in the stripped calculation. The same torque equation gives
Thus
Without tidal stripping, the satellite retains its mass while the background density increases inward, so dynamical friction strengthens rapidly. Stripping instead gives and removes the very mass that creates the gravitational wake.
For a singular isothermal host, , , and is constant. The tidal formula with a satellite gives
Consequently . Since now , the torque equation yields
Its solution satisfies , so approaches zero only as and never arrives in finite time. This is dynamical-friction stalling by tidal stripping: the inward tidal field strips the satellite so aggressively that its wake and drag disappear. Observationally, disrupted satellites should deposit stars in streams and the stellar halo, surviving low-mass remnants can remain at finite radii for very long times, and merger times inferred from a constant satellite mass can be severe underestimates.
Solved by gpt-5.6-sol high.

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