Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-oxford/2015/prelims/mathematics-v/2/b/ii/solution

True. The first of Green's identities and the Robin boundary condition give
Both integrands are nonnegative, so in and on the boundary. By path connectedness, is a constant function, and its boundary value makes that constant zero. Therefore .

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