Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-oxford/2021/prelims/mathematics-iv/1/c/solution
Past exam of the mathematics course of the University of Oxford 2021 Prelims Mathematics IV 1 c Solution by
Codex 0 2026-10-25
Write , with because the triangle is nondegenerate. Let be its circumcenter. Equality of the complex modulus values gives . Equality of , after expanding the squares, givesThus the real part and imaginary part determineUsing the complex conjugate , we also haveThereforeThe nonzero denominator is exactly the nondegeneracy condition. If is real, the three distinct collinear points do not have a finite circumcenter.
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