Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-oxford/2021/prelims/mathematics-v-resit/question-6/b/solution

Set in Laplace's equation. Separation of variables gives
The Sturm-Liouville problem in has the constant mode with , and the eigenfunctions with , . Indeed, integration by parts makes nonnegative; for the first Neumann boundary condition removes the sine term and the second requires to be an integer. For , both derivative conditions make constant.
Expand the top data using a Fourier cosine series:
The constant coefficient is
For , the constant part has zero integral against , and two integrations by parts give
Since the bottom value is zero, a convenient factor depending on for the nonconstant modes is , which vanishes at . Its value at is . The zero mode is linear in , so matching both constant boundary values gives
To obtain exactly the paper's form, use the hyperbolic-function identity
Thus
Each product of hyperbolic sine or hyperbolic cosine with has . The zero mode is also a harmonic function. On , the factor lies between zero and one. Since converges, the Weierstrass M-test gives uniform convergence on the closed rectangle. The series therefore gives zero at the bottom and the continuous Fourier cosine series of at the top, including its endpoints. On compact subsets with , the factors decay exponentially with , justifying termwise partial derivatives. In particular on both open vertical edges because every differentiated cosine factor vanishes there. The solution has finite Dirichlet energy: Fourier orthogonality gives the th nonconstant mode's energy as , whose sum is finite. Here is the hyperbolic cotangent. Thus a proves uniqueness in that class.
There is a corner compatibility condition for mixed boundary data in the printed wording. The top data have , but the paper writes even at . The series solves the interior equation and all the open-edge boundary conditions; the literal derivative condition at is incompatible with the top data. A function differentiable in along the top edge would necessarily have . Hence it cannot simultaneously satisfy the printed zero derivative at that corner, and there is no solution with all those literal corner requirements. The standard interpretation of this mixed boundary condition imposes the Neumann boundary condition on the open sides and the Dirichlet boundary condition continuously on the horizontal edges. Differentiating the series term by term on the top edge would be invalid at this corner; the uniform convergence of the undifferentiated series does not license that operation.

New to topics? Read the docs here!