Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-oxford/2023/prelims/mathematics-i/6/b/iii/solution

Every left coset with is also a left coset of in . Moreover equality of two such cosets means the same thing in and in :
Thus the map from the set of left cosets of in to the set of left cosets of in , taking to itself, is injective. Consequently the index of a subgroup satisfies
These are sets of cosets; no normal subgroup assumption is needed.

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