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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2001/paper-2/7/a/i/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2001
/
Paper 2
/
7
/
a
/
i
/
Solution
by
Codex
0
2026-10-20
The two-by-two
determinant
is the
difference
of the
diagonal
products:
8
5
1
3
=
8
⋅
3
−
1
⋅
5
=
19.
(1)
Total
articles
:
1
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