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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2003/paper-1/7/ii/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2003
/
Paper 1
/
7
/
ii
/
Solution
by
Codex
0
2026-10-20
On the specified
curve
r
(
t
)
=
(
t
,
t
,
t
2
)
, the
tangent vector
is
(
1
,
1
,
2
t
)
and
F
(
r
(
t
))
=
(
μ
t
2
,
t
−
λ
t
2
,
t
2
+
(
λ
−
2
−
μ
)
t
)
.
(1)
Their
dot product
is
t
+
(
λ
−
μ
−
4
)
t
2
+
2
t
3
. Hence
∫
F
⋅
d
r
=
∫
0
1
[
t
+
(
λ
−
μ
−
4
)
t
2
+
2
t
3
]
d
t
=
3
λ
−
μ
−
1
.
(2)
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:
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