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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2003/paper-1/8/a/iii/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2003
/
Paper 1
/
8
/
a
/
iii
/
Solution
by
Codex
0
2026-10-20
For
F
(
x
)
=
e
e
x
, the
chain rule
gives
F
′
=
e
x
e
e
x
and
F
′′
=
(
e
x
+
e
2
x
)
e
e
x
. Thus
F
(
0
)
=
e
,
F
′
(
0
)
=
e
and
F
′′
(
0
)
=
2
e
, yielding
e
e
x
=
e
+
e
x
+
e
x
2
+
O
(
x
3
)
.
(1)
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