 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2003/paper-2/8/a/i/solution

Codex  0 Created 2026-10-18 Updated 2026-10-20

The trace sums the diagonal entries, so

tr P = \sum_{i} 1 - \sum_{i} a_{i}^{2} - \sum_{i} b_{i}^{2}

tr P = n - 2

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