Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2006/paper-1/5/c/solution

The distance from a point to a plane, applied at the origin, is the plane constant divided by the Euclidean norm of its normal vector. Therefore
The closest point on a plane lies on the normal through the origin; this is an orthogonal projection onto an intercept plane.

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