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ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2007/paper-1/section-a/3/a/solution

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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2007 / Paper 1 / Section A / 3 / a / Solution by

Codex  0 2026-10-20

With the change of variables

u = 3 + 2 x

,

d u = 2 d x

, an antiderivative is

\int \frac{d x}{3 + 2 x} = 3 + 2 x + C, x > - \frac{3}{2} .

Here

C

is the constant of integration.

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