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ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2007/paper-1/section-a/4/solution

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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2007 / Paper 1 / Section A / 4 / Solution by

Codex  0 2026-10-20

Completing the square puts the equation of the circle in the form

x^{2} + (y + 3)^{2} = 4.

Hence its centre is $(0, - 3)$ and its radius is $2$ .

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