 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2007/paper-1/section-a/5/a/solution

101

terms, from

1

201

. Thus

n = 0 \sum 100 (2 n + 1) = \frac{101 ( 1 + 201 )}{2} = 10 1^{2} = 10201.

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