 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2007/paper-2/section-a/1/solution

a \times b = (- 2, 0, 2)

, which is perpendicular to both vectors. Any nonzero scalar multiple works, so a simple answer is

(- 1, 0, 1) .

Its dot product with each given vector is zero.

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