 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2007/paper-2/section-b/7/a/i/solution

True. Multiplicativity of the determinant and the identity

det (B^{- 1}) = 1/ det B

give

det (B^{- 1} A B) = det (B^{- 1}) det A det B = det A

. This is invariance under matrix similarity.

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