 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2007/paper-2/section-b/7/d/i/solution

Subtracting the first and third equations gives

μ (x - z) = 0

. Since

μ \neq = 0

x = z

, and the second equation gives

x = z = 1

. The first then gives

y = 1 - μ

, so the unique solution of the system of linear equations is

(x, y, z) = (1, 1 - μ, 1) .

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