 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2008/paper-1/18/a/ii/solution

Codex  0 Created 2026-10-18 Updated 2026-10-20

- 1 2 - 3 20 - 2 - 3 - 2 3

. Transposing and dividing by the nonzero determinant gives the inverse matrix

S^{- 1} = 1/4 - 1/2 3/4 - 1/2 0 1/2 3/4 1/2 - 3/4 .

S

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