 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2008/paper-2/11/a/i/solution

Codex  0 Created 2026-10-18 Updated 2026-10-20

Every set of

S

students is equally likely to be the specified college. There are

(S N)

choices in total and

(S L)

choices consisting entirely of the specified group. Therefore the hypergeometric distribution gives

P (all lazy) = \frac{( S L )}{( S N )} .

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