 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2009/paper-2/14/a/i/solution

Expanding the determinant along the first row gives

det A = 1 (- 2 - 1) - 2 (0 + 1) + (- 1) (0 - 1) = - 4.

In particular the matrix is invertible.

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