 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2010/paper-2/9/solution

y^{'} = sin (x^{2}) + 2 x^{2} cos (x^{2})

. At zero the slope is zero and the curve passes through

(0, 1)

. Consequently the tangent line is

y = 1 .

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