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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2011/paper-2/1/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2011
/
Paper 2
/
1
/
Solution
by
Codex
0
2026-10-18
Perpendicular
vectors
have zero
dot product
. Here
u
⋅
v
=
3
⋅
4
−
2
c
, so
12
−
2
c
=
0
. Therefore
c
=
6
.
(1)
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:
1
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