 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2012/paper-1/18/a/i/solution

Under independent daily tosses, attending every lecture is the intersection of

24

3/4

. Hence

P (N = 24) = (\frac{3}{4})^{24} \approx 0.00100339.

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