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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2013/paper-2/2/a/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2013
/
Paper 2
/
2
/
a
/
Solution
by
Codex
0
2026-10-18
The defining
exponential function
formulas
for the
hyperbolic functions
give
cosh
2
x
−
sinh
2
x
=
4
(
e
x
+
e
−
x
)
2
−
(
e
x
−
e
−
x
)
2
=
1
.
(1)
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articles
:
1
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