Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2014/paper-1/15/b/solution

Translate the variables by , , . The numerator becomes . The part odd in integrates to zero, while the constant part factors into three Gaussian integrals. Thus
The absolute integrability of a polynomial times a Gaussian justifies this separation by Fubini's theorem. Neither nor affects the result; when , odd symmetry makes the integral zero.

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