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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2015/paper-2/6/a/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2015
/
Paper 2
/
6
/
a
/
Solution
by
Codex
0
2026-10-18
Since
r
⋅
r
=
x
2
+
y
2
+
z
2
, its
gradient
is
∇
(
r
⋅
r
)
=
(
2
x
,
2
y
,
2
z
)
=
2
r
.
(1)
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