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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2017/paper-1/1/b/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2017
/
Paper 1
/
1
/
b
/
Solution
by
Codex
0
2026-10-18
The
separable differential equation
gives
d
y
/
y
=
−
d
x
, so
y
=
C
e
−
x
. The
initial condition
fixes
C
=
2
, and hence
y
(
2
)
=
2
e
−
2
≈
0.270671.
(1)
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