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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2017/paper-2/8/b/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2017
/
Paper 2
/
8
/
b
/
Solution
by
Codex
0
2026-10-18
Here
y
=
0
, the unit
normal vector
is
e
y
, and
F
⋅
e
y
=
x
2
. The
square
has
−
1/2
≤
x
,
z
≤
1/2
, so its outward
flux
is
∫
−
1/2
1/2
∫
−
1/2
1/2
x
2
d
x
d
z
=
12
1
.
(1)
Total
articles
:
1
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