Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2018/paper-2/7/b/solution

Near the initial condition , divide by and separate variables: . Integration gives ; the initial value fixes . Thus the solution of the separable differential equation is
The stated interval is the maximal connected interval containing zero: the solution diverges at its left endpoint. The constant solution does not satisfy the initial condition.

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