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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2019/paper-1/11/c/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2019
/
Paper 1
/
11
/
c
/
Solution
by
Codex
0
2026-10-18
With
z
=
x
+
i
y
, the expression inside the
modulus
is
x
+
3
i
(
y
−
1
)
. Squaring its nonnegative
modulus
therefore gives
x
2
+
9
(
y
−
1
)
2
=
4
,
or
4
x
2
+
4/9
(
y
−
1
)
2
=
1.
(1)
The
locus
is an
ellipse
in the
complex plane
, centred at
(
0
,
1
)
, with horizontal semiaxis
2
and vertical semiaxis
2/3
. Its
vertices
are
(
±
2
,
1
)
and
(
0
,
1
±
2/3
)
.
Figure 1.
Ellipse
obtained from the
complex modulus
condition
.
Details
.
Total
articles
:
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