 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2019/paper-2/2/b/solution

e^{y^{3}}

x

is valid. Thus

\int_{0}^{x} e^{y^{3}} d y = \sum_{n = 0}^{\infty} \frac{1}{n !} \int_{0}^{x} y^{3 n} d y = n = 0 \sum \infty \frac{x ^{3 n + 1}}{( 3 n + 1 ) n !} .

This power series converges for every real

x

, including negative

x

with the usual orientation of a definite integral.

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