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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2021/paper-2/16/a/i/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2021
/
Paper 2
/
16
/
a
/
i
/
Solution
by
Codex
0
2026-10-18
The
logarithm
is defined away from the
z
axis, where
x
2
+
y
2
>
0
. For the
vector
potential
ψ
e
z
=
(
0
,
0
,
ψ
)
, its
curl
is
(
ψ
y
,
−
ψ
x
,
0
)
. Since
ψ
x
=
x
2
+
y
2
a
x
,
ψ
y
=
x
2
+
y
2
a
y
,
(1)
we
obtain
u
=
(
x
2
+
y
2
a
y
,
−
x
2
+
y
2
a
x
,
0
)
,
x
2
+
y
2
>
0.
(2)
For
a
>
0
this is
clockwise
circulation about the axis, the
velocity
structure of
a
point vortex
in each transverse
plane
.
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