 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2022/paper-2/14/c/solution

Each tree independently has ten equally likely integer yields. Of the

100

(30, 32), (31, 31), (32, 30)

sum to sixty-two. Thus

P (62 seeds) = \frac{3}{100} .

The uniform distribution on a finite set applies to the individual yields, not to their sum.

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