Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2022/paper-2/3/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2022 Paper 2 3 Solution by
Codex 0 2026-10-18
The equation is not separable, because cannot be written as a product of a function of and a function of on an open region. For example, the ratio depends on for distinct fixed , whereas a separated product would give a constant ratio.
It is not homogeneous in the sense of a homogeneous first-order differential equation: the right-hand side is not a function of alone. It is also not a homogeneous linear differential equation, since moving the term to the left leaves a nonzero forcing.
It is linear, since it has the standard linear ordinary differential equation formThus the classifications are (a) no, (b) no, (c) yes.
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