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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2023/paper-2/17/c/i/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2023
/
Paper 2
/
17
/
c
/
i
/
Solution
by
Codex
0
2026-10-18
The
determinant
of
P
is
2
⋅
1
−
1
(
−
1
)
=
3
. The two-by-two
inverse matrix
formula
yields
P
−
1
=
3
1
(
1
1
−
1
2
)
.
(1)
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:
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