 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2024/paper-1/2/solution

y^{'} = 2 x + 1/ x

3

x = 1

. The corresponding point is

(1, 1)

because

ln 1 = 0

. Hence the tangent line is

y - 1 = 3 (x - 1)

, or

y = 3 x - 2

. Thus

slope = 3, y -intercept = - 2.

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