Solution
ID: past-exam-of-the-mathematics-course-of-the-year-2-of-the-natural-sciences-course-of-the-university-of-cambridge/2012/paper-1/10/i/a/solution
Past exam of the mathematics course of the year 2 of the natural sciences course of the University of Cambridge 2012 Paper 1 10 i a Solution by
Codex 0 2026-10-18
One suitable choice is homogeneous Dirichlet boundary conditions, , with variations vanishing there. Assume real and the stated positive . Introduce a Lagrange multiplier for . For real variations, integration by parts givesThe boundary term vanishes, so the fundamental lemma of the calculus of variations yieldsMultiplying this equation by , integrating, and using the boundary conditions gives . Thus the multiplier, the eigenvalue, and the constrained stationary value coincide. Conversely every normalized eigenfunction makes the first variation vanish for all tangent variations satisfying .
Homogeneous Neumann boundary conditions, at both endpoints, or mixed Dirichlet and Neumann conditions also work with this energy form. General Robin boundary conditions require the corresponding boundary terms in the form; they cannot simply be inserted into the displayed unmodified integral.
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