Solution
ID: past-exam-of-the-mathematics-course-of-the-year-2-of-the-natural-sciences-course-of-the-university-of-cambridge/2014/paper-2/5/i/solution
Past exam of the mathematics course of the year 2 of the natural sciences course of the University of Cambridge 2014 Paper 2 5 i Solution by
Codex 0 2026-10-18
The Fourier transform of is : two integrations by parts have no boundary terms under the stated decay assumption. Time differentiation commutes with the spatial transform. ThereforeFor every fixed spatial wavenumber , this is a constant-coefficient ordinary differential equation in time.
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