Solution

ID: past-exam-of-the-mathematics-course-of-the-year-2-of-the-natural-sciences-course-of-the-university-of-cambridge/2015/paper-1/2/b/solution

After multiplying the initial field by , the dependence is exactly the cosine mode. Its orthogonality therefore gives when . For , the remaining Fourier coefficient in the Fourier sine series is
Thus
The coefficients are independent of , because the initial exponential exactly cancels the drift-removing weight. Substitution into the preceding expansion gives the full subsequent solution, with decay rates .

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