Solution

ID: past-exam-of-the-mathematics-course-of-the-year-2-of-the-natural-sciences-course-of-the-university-of-cambridge/2023/paper-2/8/b/solution

For a subgroup and , the left and right cosets are and . A normal subgroup satisfies for every . Multiplying this set equality on the right by gives
Conversely this equality implies , so it is an equivalent definition of normality.

New to topics? Read the docs here!