 Solution

By part (c), one-consistency gives Sigma-1 soundness and hence ordinary consistency. First, $S$ cannot prove $\neg G$: if it did, the diagonal equivalence would give $S⊢\square G$. This is a ${\Sigma }_1$ sentence, so soundness would make it true. The stipulated standard interpretation of the arithmetical provability predicate would then supply an actual proof of $G$, contradicting consistency.

Now suppose $S⊢\square \neg G$. This too is a ${\Sigma }_1$ theorem. Soundness and the standard correctness of the predicate would imply that there is an actual $S$-proof of $\neg G$, which was just excluded. ThereforeThe two applications of soundness concern the provability assertions, not the truth of arbitrary arithmetic sentences.