 Solution

Yes. Give players $1,2,3$ weights $1,1,2$, respectively, and let the quota be three. This weighted voting game is a simple cooperative game whose minimal winning coalitions are $\{1,3\}$ and $\{2,3\}$. In orders $123,132,213,231$, player 3 supplies the winning marginal contribution. In order $312$ player 1 does, and in order $321$ player 2 does. Averaging the six marginal contribution vectors gives exactly $(1/6,1/6,4/6)$ as the vector of Shapley values.