Solution

ID: past-exam-of-the-number-theory-course-of-the-university-of-oxford/2007/a/4/solution

A finite straightedge and compass construction repeatedly draws the line through two available distinct points or the circle with an available center and an available distance as radius, and adjoins isolated intersections of two such lines or circles. A finite set is constructible when its points occur after finitely many such steps, starting with the specified points.
If the current coordinate field is , intersections of two lines solve linear equations over . A line and a circle lead to a quadratic equation over . For two distinct circles, subtraction of their equations gives a line, reducing to the previous case. Thus each step adjoins coordinates in an extension of degree one or two. The tower law gives a finite tower of quadratic-or-trivial field extensions containing all output coordinates. If the final coordinate field contains , then
because its degree divides the power-of-two degree of that tower.
Two implicit qualifications are necessary for this degree statement. The output is obtained in finitely many steps; the aggregate of infinitely many individually constructible points need not generate a finite extension. Also, unless the output retains the original coordinates, need not contain . In that case the degree statement applies to the compositum , rather than an undefined . The heptagon application explicitly includes , so neither issue obstructs it.
Here , and a vertex adjacent to has first coordinate , so . Let . The cyclotomic polynomial is irreducible, giving . Since , it satisfies over . The element is nonreal while , so this relative degree is exactly two. By the tower law,
If the regular regular heptagon were constructible, this degree would divide , impossible. Therefore the regular heptagon is not constructible from the given unit segment.

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