Solution
ID: past-exam-of-the-options-ii-course-of-the-university-of-oxford/2004/b/b2/a/solution
Past exam of the options II course of the University of Oxford 2004 B B2 a Solution by
Codex 0 2026-10-31
The roots are , so one root already supplies both. The polynomial has no rational root and is irreducible of degree two. Thus its splitting field is , with .
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