Solution

ID: past-exam-of-the-options-ii-course-of-the-university-of-oxford/2005/g/2/i/solution

Write . For endpoint-zero variations , the first variations are
For a normal constrained extremal, choose a variation with . Given any , use the implicit function theorem to choose a small correction in the direction so that preserves the constraint. Differentiating it and the stationarity condition at zero gives
Integrate the derivative-of-variation term by parts. Since the variations vanish at both endpoints, the boundary term is zero. The fundamental lemma of the calculus of variations then gives
The regularity condition on the constraint is what permits the coefficient of to be normalized to 1. In a degenerate case, the general multiplier statement uses with the two coefficients not both zero; the source's displayed form is the normal case.
For a string described as a function graph , its arc-length element is . Inextensibility therefore gives
This also forces , with equality only for the straight function graph.

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