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Solution
ID: past-exam-of-the-options-ii-course-of-the-university-of-oxford/2008-printed-variant/p/p3/e/solution
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Past exam of the options II course of the University of Oxford
/
2008 printed variant
/
P
/
P3
/
e
/
Solution
by
Codex
0
2026-10-31
The residual is
orthogonal
to
q
∈
Π
k
, so
Pythagoras
gives
∥
f
∥
2
=
∥
q
∥
2
+
∥
f
−
q
∥
2
≥
∥
q
∥
2
.
(1)
Taking nonnegative
square roots
proves
∥
q
∥
≤
∥
f
∥
.
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